The 5 ways to visualize complex functions | Essence of complex analysis #3
Why Mathematics Stack Exchange recommends it
Mathematics Stack Exchange users link it when someone wants to see what complex functions and polynomial roots look like.
Recommended by 2 people across 2 different months, 2021 to 2024.
What it is
A 14-minute explainer from the Mathemaniac channel, part 3 of the Essence of complex analysis series, on how to visualize complex functions, which map 2D inputs to 2D outputs and so live in four dimensions. It walks through five different visualization approaches with plenty of animations.
What people said
Recommends Daniel · 2021-12 · Mathematics Stack Exchange · on “Elementary Linear Algebra Question”
I googled 'visual complex functions' and, in addition to the book you mentioned, a good video appeared: [this video]
Recommends ConMan · 2024-02 · Mathematics Stack Exchange · on “Understanding and Visualizing Complex Roots According to the Fundamental Theorem of Algebra”
While FTOA tells us that every polynomial has a certain number of roots, it doesn't give us a method for finding them. In general, while the roots of any linear or quadratic polynomial can be found through basic algebra, finding the roots of a cubic or quartic is quite difficult and for quintics and higher there is no guarantee that the roots can be exactly calculated. Beyond that, many of the methods used for working with real roots can be extended to complex numbers, for example: Vieta's formulas [LINK] still apply. A version of the rational root theorem [LINK] can be written in terms of Gaussian rationals [LINK] . If you can find some of the roots exactly, you can perform polynomial long
Cites Sammy Black · 2022-07 · Mathematics Stack Exchange · on “Images of curves passing through zeros of a complex polynomials”
The "bouncing" of the graph of a polynomial of even multiplicity over the reals is a direct consequence of the fact that $(-x)^{2n} = x^{2n}$ for any natural $n$ . For a given polynomial $p(x)$ and root $r$ of multiplicity $2n$ , you can see this behavior more clearly by constructing a particular approximating polynomial $\hat{p}(x) = \hat{p}_r(x)$ obtained by evaluating $x=r$ in all but the factors of $(x-r)$ . In other words, write $p(x) = q(x) \, (x-r)^{2n}$ for some polynomial $q(x)$ such that $q(r) \neq 0$ . Then, we define the approximation $\hat{p}(x) = q(r) \, (x-r)^{2n}$ . Since $$ \lim_{x \to r} \frac{p(x)}{\hat{p}(x)} = \lim_{x \to r} \frac{q(x)}{q(r)} = 1, $$ we can see that $\ha