Lecture 2: Topological Manifolds (International Winter School on Gravity and Light 2015)
Why Mathematics Stack Exchange recommends it
Mathematics Stack Exchange users link it as a clear, rigorous introduction to topological manifolds and charts for people struggling with the definitions.
Recommended by 4 people across 4 different months, 2018 to 2023.
What it is
Lecture 2 of Frederic Schuller's 24-lecture general relativity course at the 2015 International Winter School on Gravity and Light in Linz. It defines topological manifolds, charts and dimension, building on the topology introduced in Lecture 1. The course aims at ambitious undergraduates through beginning PhD students in math and physics.
What people said
Recommends Nicolas Lussier-Clément · 2018-03 · Mathematics Stack Exchange · on “Manifolds and open sets in them with different dimensions”
Just to warn, I'm fairly new to this discipline so you might verify further. From Lecture 1 of Gravity and light [LINK] and books, I understood that a topological space is a set $M$ equip with a topology $\mathscr{O}_M)$ that is a subset of the power set of $M$, $(M,\mathscr{O}_M)|\mathscr{O}_M\subset\mathscr{P}(M)$. The topology $\mathscr{O}_M)$ must satisfy 3 additional axiom: $\varnothing, M \in\mathscr{O}_M$ $U,V\in \mathscr{O}_M \Rightarrow U \cap V \in \mathscr{O}_M$ $U_\alpha\in \mathscr{O}_M \Rightarrow \left( \bigcup\limits_{\alpha \in A} U_\alpha \right) \in \mathscr{O}_M$ Meaning that the topological space does not carry dimensions and in that sense you might be able to define suc
Recommends marc · 2018-05 · Mathematics Stack Exchange · on “d-dimensional topological manifold example”
I am having trouble understanding the concepts of manifolds, so I recently watched these two videos on the topic topology [LINK] manifolds [this video] . During watching I came up with the following example, for which I will briefly denote the required definitions I am trying to grasp first. The definition in question given for a $d$-dimensional topological manifold is: Definition : A topological space $(M, \mathcal{O})$ is called a d-dimensional topological manifold , if $$ \forall p \in M : \exists \mathcal{U} \in \mathcal{O} : \exists x : \mathcal{U} \to x(\mathcal{U}) \subseteq \mathbb{R}^d,$$ such that $x$ is invertible: $x^{-1} : x(\mathcal{U}) \to \mathcal{U}$ $x$ is continuous $x^{-1}$ is
Recommends Antoni Parellada · 2021-05 · Mathematics Stack Exchange · on “Where does the metric enter the picture in the definition of the standard topology?”
Here is the exact moment [this video] where this is discussed. I think the video is excellent, but I am just not presenting my question properly.
Recommends Ben H · 2022-12 · Mathematics Stack Exchange · on “Could you give me advice on self-study for topology, measure theory and functional analysis?”
Check out the lectures by Frederic Schuller. You can watch the first two in his GR lecture series, on Topology [LINK] and on Topological Manifolds [this video] , to see if you like his style, and then try Lectures on Quantum Theory [LINK] , which are highly mathematical, following von Neumann's functional analysis approach (and have a standalone lecture on Measure Theory [LINK] ). Paired with appropriate textbooks for further reference, they're perfect.
Cites marcoqc · 2023-09 · Mathematics Stack Exchange · on “Bifurcations and topological manifolds”
I'm following an online course on Differential Geometry by F. Schuller and in this lesson [this video] , around 23:00, he draws a bifurcation and says that isn't a topological manifold because any open set around the bifurcation can't be mapped continuously and with continuous inverse to $\mathbb{R}$ , $\mathbb{R}^2$ , $\mathbb{R}^3$ , etc. [LINK] I don't understand why. If we take $\mathbb{R}^2$ , I can take every point of the bifurcation and map it to a curve in $\mathbb{R}^2$ (so, a section of $\mathbb{R}^2$ ) that looks like a Y. Similarly, I can take any point of that curve and map it back to the manifold. What is the problem here? I get why it isn't a differentiable manifold, but why not a
Critical marc · 2018-05 · Mathematics Stack Exchange · on “d-dimensional topological manifold example”
@freakish Okay. got it. Unfortunately there was this very misleading part [this video] of the lecture, where I got the incomplete definition from. So basically I assume I have to require as you said the target of the chart to be $x(\mathcal{U}) = W\in \mathcal{O}_\text{standard}$, which makes intuitively sense when working with continuity in real spaces, as it gives the known "neighbourhoods" of elements. Of course this might add a number of points to the target set, but then their preimages are the empty set.