Electric field inside a charged ring

What people said

Cites J.G. · 2017-03 · Physics Stack Exchange · on “Why is the Electric Field inside a hollow sphere zero but not for a ring?”

Given a sphere or ring with charges on the surface or perimeter but no interior charges, each interior point is on the surface of a sphere of smaller radius concentric with the original sphere or ring. The usual proof with Gauss that $E=0$ inside the sphere, or equivalently that $=0$ across the surface of the interior sphere, relies on the problem's spherical symmetry. Since a ring lacks spherical symmetry, we cannot prove a spherically symmetric electric field on the surface of such an interior sphere (which extends beyond the ring's plane, but intersects said plane with a circle enclosed in the ring). Nor does the 2D symmetry of the problem prove a 2D symmetry around the "Equator" of such

Cites Ranjeet Mishra · 2019-06 · Physics Stack Exchange · on “Electric field inside infinite charged hollow cylinder”

Gauss's Law says that electric field inside an infinite hollow cylinder is zero. My question however is that an infinite hollow cylinder can be constructed by taking rings as element and the field produced by a ring within it is non zero. electric field inside a ring [this video] . Wouldn't this imply that there would exist a field inside an infinite hollow cylinder?

Cites slartibartfast the second · 2020-07 · Physics Stack Exchange · on “Field due to a hollow cylinder via analogy to a circle”

It seems that most people agree to the field inside a hollow cylinder being zero but I’m troubled when I consider the case of a ring shaped linear distribution of charge. It is known that the electric field due to a ring charge distribution inside it(in the plane) is non zero (don’t take my word for it, [this video] ) Suppose we consider the ring shaped lamina of the cylinder that lies in the horizontal plane perpendicular to the axis of the infinite cylinder. The field due to it would be non-zero and radially inward as Ive said above, but now we consider the rest of the cylinder. Now, In order for the field inside to be zero, it would mean that the field caused due to the rest is in the opposite

Cites Ali Pedram · 2022-01 · Physics Stack Exchange · on “Application of Gauss Law to Find the Electric Field for an Arbitrary Point in a Ring of Charge in 2D (and Similar Problems)”

I checked the website for a similar problem but although there are other questions with a similar title, I couldn't find any question which directly deals with my problem. This question might be trivial but for some reason I have difficulty understanding it. Imagine a uniformly charged ring. A picture is given below for clarity. We want to find the electric field in an arbitrary point inside the circular ring (point $P$ ). The primed coordinates are source coordinates and the others are field coordinates. Just to make it clear, I am not talking about analyzing a 3D object in a 2D plane. Imagine the whole universe is 2D and we want to solve this electrostatics problem in that universe. [LINK]

Cites İbrahim İpek · 2023-05 · Physics Stack Exchange · on “If the electric field inside an infinitely long charged cylinder is non-zero except origin, how can be the inward flux zero?”

If the electric field inside an infinitely long charged cylinder is non-zero except origin, how can be the inward flux zero? [this video] If we look at this video, we would see that a charged ring has a non-zero E-field inside it except for the origin. A cylinder can be constructed by infinitely many rings, and their vertical components would just cancel out each other to give us back the same formula. [LINK] So if we place inside a surface S (let's say another cylinder), I can't understand how can the net flux into the S be zero. Gaussian law tells us that the flux passing through a surface is exactly the sum of charges in it. Flux has to be zero because we have no charges inside S. But I am not