Android Studio Tutorial - NEW Login Register #1 - UI Design
Why Stack Overflow recommends it
Stack Overflow users link it as the tutorial they followed to build an Android login/register system with Volley, PHP and MySQL, usually when asking for debugging help.
Recommended by 2 people across 2 different months, 2016 to 2019.
What it is
A short Android Studio tutorial by TonikamiTV that starts a remade login and register app, covering the UI design for the screens. The series later uses Volley to talk to a PHP and MySQL backend, and the author publishes the full source code on GitHub.
What people said
Recommends Eric Reyna · 2016-06 · Stack Overflow · on “Best way to send data through devices? (Android)”
An Online database will work. You can store the database locally on the phone and have it refresh every "X" amount of time. You will have to use some PHP coding and query the data from the database, sending it back to the phone. You can find a free webhost that lets you store databases here [LINK] . Hope this helps. Also look into importing sqlite database libraries and mysql handlers to implement this. Tweak this example on Youtube to get webhost working and a simple login via php here [this video]
Recommends J.Marris · 2016-10 · Stack Overflow · on “How to use CONCAT and NOT LIKE in an SQL Update in PHP request”
@Leo link [this video] If you see that link its a tutorial for how to use php with android studio. Quick answer: You add your php file to online db, then you reference the url in yours java code, that is how you run it.
Cites Jeremy Levasseur · 2016-08 · Stack Overflow · on “Connecting MySQL database to Android Application using android studio and 000webhost”
I am trying to build a user database for an android application and I am following the tutorials made by Tonikami ( [this video] ). I believe that I have replicated his code but I still cannot pass data from the application to the database. Here is my Register Activity: package com.example.jerem.myapplication; import android.content.Intent; import android.support.v7.app.AlertDialog; import android.support.v7.app.AppCompatActivity; import android.os.Bundle; import android.view.View; import android.widget.Button; import android.widget.EditText; import com.android.volley.RequestQueue; import com.android.volley.Response; import com.android.volley.toolbox.Volley; import org.json.JSONException; import
Cites Lechat Noir · 2016-08 · Stack Overflow · on “Android studio Login/Register ERROR”
I've create an application LOGIN/REGISTER with this tutorial [this video] . My problem is, if I put nothing on the register view of my app (name, username, age, password), it create an user on my table with nothing inside (just a number on "user_id" column) and I can sign in with nothing in "username" and "password" on the login view of my app. And all my LOGIN/REGISTER android app becomes useless... If you don't understand what I say, you can try my app [LINK] . For information, I've change some element to not give you all access to my app : In "LoginRequest.class", I have change my website by xxx at this line : private static final String LOGIN_REQUEST_URL =" [LINK] "; In "RegisterRequest.class
Cites Nulle · 2016-09 · Stack Overflow · on “Another PHP JSONException: Value <br of type java.lang.String cannot be converted to JSONObject”
So i am trying to create a registersite on my android app. I have been following Toni Kami step by step guide [this video] Atm Im at a complete halt and up to hours trying to fix a json exception that im having and i now desperately turn to your fine people for help. the error goes like this: [LINK] RegisterActivity.java = [LINK] RegisterRequest.java = [LINK] register.php = [LINK] I read around that in most cases it is the URL thats the problem but when i paste the url in chrome then it does echo connected. this is the return string: I/tagconvertstr: [ Notice : Undefined variable: con in C:\xampp\htdocs\Yield\PhpFiles\register.php on line 12 Warning : mysqli_prepare() expects parameter 1 to be my
Cites Andreas Konstantakos · 2017-04 · Stack Overflow · on “Runtime errors in my BackgroundTask and RegisterActivity”
I suggest you to use Volley Library to achieve a Login - Register Activity. It is the latest trend in android develoment and much more easier than past methods. I will give you an example for the register activity: My register.xml: <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android=" [LINK] " android:orientation="vertical" android:layout_width="match_parent" android:layout_height="match_parent" android:padding="@dimen/activity_horizontal_margin" android:background="@drawable/icon13"> <EditText android:layout_width="match_parent" android:layout_height="wrap_content" android:inputType="textPersonName" android:ems="10" android:maxLength="16" android:id="@+id/etName" android:layo
Cites Alien Java · 2017-05 · Stack Overflow · on “org.json.JSONException: End of input at character XYZ”
yes my friend i tried to log in but i get same issue :(. in response is comming a data from the server. video tutorial: [this video]
Cites Alien Java · 2017-05 · Stack Overflow · on “org.json.JSONException: End of input at character XYZ”
I know that this issue is well known, but I can't solve it so far. In the end, I have a project and the data is stored perfectly in the DB (localhost). I'm using [LINK] The problem isn't in the PHP files or something with the connection of my app. Source [this video] . The issue happens with JSONObject jsonResponse = new JSONObject(response); In this SO post org.json.JSONException: End of input at character [LINK] somebody wrote that the solution is: Change JSONObject jsonObject = new JSONObject(result); to result=getJSONUrl(url); //<< get json string from server JSONObject jsonObject = new JSONObject(result); but in my app the method getJSONUrl doesn't exist, so that option doesn't work for me.
Cites Gustavo Contreiras · 2017-09 · Stack Overflow · on “Anything I try to store on database enters with value '0'”
I've made a Login/Register app folowing this tutorial: [this video] Everything was ok, but then I deleted the "age" parameter and inserted a "lastname" and a "email" parameter. So, everytime I try to register an user, the "email" field goes with value "0" (even if I dont use @ or .) That's my Register.php file: <?php require("Password.php"); $connect = mysqli_connect("x", "x", "x", "x"); $name = $_POST["name"]; $lastname = $_POST["lastname"]; $email = $_POST["email"]; $password = $_POST["password"]; function registerUser() { global $connect, $name, $lastname, $email, $password; $passwordHash = password_hash($password, PASSWORD_DEFAULT); $statement = mysqli_prepare($connect, "INSERT INTO user (nam
Cites Jamescl21 · 2019-01 · Stack Overflow · on “Unable to login to Android app using hashed password”
I have been following a tutorial in order to create a login for an Android based application, however after encrypting the passwords I am unable to get authenticate users. I have been searching for a solution to the problem for a few days now and still no luck. I am hoping that it is something simple that I have missed. Tutorial playlist on YouTube [this video] There are also loads of people in the comments that have had the same issue as me on Video 6 (Last video in the playlist). GitHub Repository for tutorial [LINK] Any support would be greatly appreciated and thank you in advanced! Register.php <?php require("password.php"); $connect = mysqli_connect("localhost", "", "", ""); $name = $_POST["